**The Short-Circuit**

Consider a resistor whose value is zero ohms. An equivalent representation of such a resistance, called a *short-circuit*, is shown below:

By Ohm’s Law: ( For short Circuit, R = 0 )

*v *= *Ri *= 0*i *= 0 V

Thus, no matter what finite value *i*(*t *) has, *v*(*t *) will be zero. Hence, we see that a *zero-ohm resistor *is equivalent to an *ideal voltage source whose value is zero volts*, provided that the current through it is finite.

**The Open-Circuit**

Consider a resistor having infinite resistance. An equivalent representation of such a resistance, called an *open-circuit*, is shown below:

By Ohm’s Law: ( For short Circuit, R = ∞ )

*i *= *v/**R *= *v/∞** *= ∞ A

Thus, no matter what finite value *v*(*t *) has, *i*(*t *) will be zero. Thus, we may conclude that an *infinite resistance *is equivalent to an *ideal current source whose value is zero amperes*, provided that the voltage across it is finite

Do they sell an electrical circuit finder to locate a short in a wall or ceiling? ware I can disconnect the wire from the 15 amp breaker and disconnect the neutral white wire and use alligator clams on both wires then use the monitor to locate the open or short circuit? Thanks, Warren