Total resistance in a parallel circuit can be found by applying Ohm’s Law. Divide the voltage across the parallel resistance by the total line current as shown in below equation.

**Example:**

Find the total resistance of the circuit shown in Figure 25 if the line voltage is 120 V and total current is 26A.

Solution :

R_{T} = V/I_{T}

R_{T} = 120 / 26 = 4.62 Ω

The total load connected to a 120 V source is the same as the single “equivalent resistance” of 4.62Ω connected across the source (Figure 26). Equivalent resistance is the total resistance a combination of loads present to a circuit.

Figure 26 Equivalent Resistance in a Parallel Circuit

The total resistance in a parallel circuit can also be found by using the below equation.

**Example 1:**

Find the total resistance of a 4Ω, and 8Ω ,and a 16Ω resistor in parallel (Figure 27).

Figure 27 Total Resistance in a Parallel Circuit

Solution :

1 / R_{T} = 1/4 + 1/8 + 1/16

R_{T} = 16/7 = 2.29 Ω

Note: Whenever resistors are in parallel, the total resistance is always smaller than any single branch.

**Example 2:**

Now add a fourth resistance of 4Ω in parallel to the circuit in Figure 27. What is the new total resistance of the circuit?

Solution:

1 / R_{T} = 1/4 + 1/8 + 1/16 + 1/4

R_{T} = 16/11 = 1.45 Ω

confused? how do you find the dividing number? base number to dived into the highest resistance total?