The sum of the currents flowing through each branch of a parallel circuit is equal to the total current flow in the circuit.

Using Ohm’s Law, the branch current for a three branch circuit equals the applied voltage divided by the resistance as shown in below equations.

**Example 1:**

Two resistors, each drawing 3A, and a third resistor, drawing 2A, are connected in parallel across a 115 volt source (Figure 23). What is total current?

Figure 23 Example 1 Parallel Circuit

I_{T} = I_{1} + I_{2} + I_{3}

I_{T} = 3 + 3 + 2 = 8 A

**Example 2:**

Two branches, R 1 and R2 , are across a 120 V power source. The total current flow is 30 A (Figure 24). Branch R1 takes 22 amps. What is the current flow in Branch R2 ?

Figure 24 Example 2 Parallel Circuit

Solution :

I_{T} = I_{1} + I_{2}

I_{2} = I_{T} – I_{1}

I_{2} = 30 -22 = 8A

**Example 3:**

A parallel circuit consists of R1 =15Ω, R2 =20Ω and R3 =10Ω, with an applied voltage of 120 V (Figure 25). What current will flow through each branch?

Figure 25 Example 3 Parallel Circuit

Solution :

I1 = V/R1 = 120/15 = 8A

I2 = V/R2 = 120/20 = 6A

I3 = V/R3 = 120/10 = 12A

I_{T} = I_{1} + I_{2 }+ I_{3 }

I_{T} = 8 + 6+ 12 = 26 A