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Reading: Formula to Calculate 4-20 mA from Process Variable
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Inst Tools > Blog > Formulas > Formula to Calculate 4-20 mA from Process Variable

Formula to Calculate 4-20 mA from Process Variable

Last updated: April 19, 2019 1:59 pm
Editorial Staff
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18 Comments
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How to Calculate 4-20mA current loop from Process Variable value of a field transmitter. Check the formula to find out equivalent 4-20mA signal from Process Variable.

Calculate 4-20mA from Process Variable

Process variable to 4-20mA Conversion

Formula :

First calculate equivalent percentage from the process variable

Percentage = ( X – LRV / URV – LRV ) . 100

Then calculate equivalent 4-20mA signal from percentage

4-20mA = ( Percentage + 25 ) / 6.25

Where,

X is Process Variable

LRV is Lower Range value

URV is Upper Range Value

Example:

A Flow transmitter has a range of 0 to 2500 m3/hr and it is displaying flow rate of 1500 m3/hr. calculate the transmitter output current.

Process variable = 1500 m3/hr

Lower Range Value, LRV = 0 m3/hr

Upper Range Value, URV = 2500 m3/hr

Note: units must be same for process variable, LRV & URV

Percentage = (1 500 – 0 / 2500 – 0 ) . 100 = 60 %

4-20 mA Signal  = (Percentage + 25) / 6.25 = (60 + 25) / 6.25 = 13.6 mA

Also you can use online Instrumentation Calculator for Automatic calculations. Click Here.

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18 Comments
  • Gunjan Raval says:
    August 29, 2016 at 3:56 pm

    Thanks for sharing

    Reply
  • Noor Mustafa says:
    August 30, 2016 at 7:21 pm

    usefull

    Reply
  • Mazhar says:
    October 19, 2016 at 7:28 am

    for calculating mA, what is 6.25 value please explain

    Reply
    • S Bharadwaj Reddy says:
      October 20, 2016 at 1:17 am

      Hello Mazhar, 100/(20-4) = 6.25

      Reply
  • Hashim says:
    November 22, 2016 at 4:11 pm

    Dear can You explain correctly how 6.25 came. While we are dividing 100/(20-4) it’s not showing 6.25

    Reply
    • S Bharadwaj Reddy says:
      November 23, 2016 at 4:07 am

      Hi, 100/(20-4) = 100/16 = 6.25

      Reply
  • Etuk Victor says:
    January 30, 2017 at 10:47 am

    Very good formula, but how did u derive or get the +25

    Reply
    • S Bharadwaj Reddy says:
      January 30, 2017 at 12:58 pm

      Hi, Percentage range is 0 to 100 i.e. starting from zero and current range is 4 to 20 i.e. starting from 4. Thats why we added 25 there. In order to get clear picture, try to calculate equivalent mA value for 0% with & without 25 in the formula.

      Reply
  • Etuk Victor says:
    January 30, 2017 at 4:01 pm

    Thanks for the clarification ?

    Reply
  • Ray says:
    April 8, 2017 at 3:57 pm

    Another simple formula for converting Percentage into equivalent 4-20mA current,
    4-20mA = (percentage*16)+ 4
    Example : 60%*16+4=13.6

    Reply
  • Danish says:
    September 25, 2017 at 4:09 pm

    how 60%+25/6.25=13.6mA,,please answer me

    Reply
    • S Bharadwaj Reddy says:
      September 25, 2017 at 4:12 pm

      Hi, Please see brackets, (60+25)/6.25 = 85/6.25 = 13.6

      Reply
  • muhammad imran ali says:
    September 28, 2017 at 6:35 am

    please check formala
    % to MA

    %= 60
    how much MA at 60%
    so
    60/6.25+4= 13.6

    Reply
  • Jagan ch says:
    September 29, 2017 at 2:54 pm

    have a one dought about a soot blowing control valve calibartion. Today I done calibartion but it is not full closed valve passing when a giving 0 commond.it is passing 5kg pressure what can I do? Please tell me a prosedure.

    Reply
  • keenam Augustine says:
    January 24, 2020 at 9:18 am

    1500*16=24000
    24000/2500=9.6
    9.6+4=13.6

    Reply
  • Mubeen says:
    February 7, 2020 at 1:02 pm

    What is the problem in this calculation…. For 20mA reading is 2500, then for x mA reading is 1500, We calculate x=20*1500/2500= 12mA… What am I missing here

    Reply
  • Sh.M AFZAL says:
    September 22, 2020 at 8:38 pm

    direct formula
    1500/2500*16+4=13.6ma

    Reply
  • Helmholtz Watson says:
    August 10, 2021 at 12:27 am

    The LRV (lower range value) will usually be 0 for flows and pressures but not for load cells, drum levels, temperatures, etc.

    For example, a -80C freezer may have a temperature transmitter calibrated from -100C to 20C. Formula 1 becomes useful. If the freezer temperature is -70C then what is the ma output from the transmitter?

    First, find the transmitter span.

    Span is URV – LRV or 20 – (-100) = 120C. Remember SPAN is always ONE number and RANGE is always TWO numbers.

    Use the formula at the top to find the percentage:

    (-70 – (-100)) / 120 = 30 / 120 = .25 or 25%.

    To find the current use one of the formulas above or : (.25 x 16) + 4 = 8 ma

    Reply

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