Diode Circuits Questions and Answers
Power Electronics Objective Questions & Answers
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When a diode is connected in series with an AC source & R load, the conduction time per cycle is
Correct!
Wrong!

For the circuit shown in the figure below, consider the diode as an ideal diode & rms value of source voltage as Vs. The output voltage waveform at R will have
Correct!
Wrong!

For the circuit shown in the figure below, V9 is the AC voltage source with peak value Vm. The waveform of the load voltage at the resistor has a
Correct!
Wrong!

The circuit shown below has the following parameters:
V1 = 8 Volts
V2 = 6 Volts
Vs = 10V/√2 (rms)
Voltage drop across D1 & D2 = 0.7 Volts
At the load (R), the peak value in the positive half cycle will be
V1 = 8 Volts
V2 = 6 Volts
Vs = 10V/√2 (rms)
Voltage drop across D1 & D2 = 0.7 Volts
At the load (R), the peak value in the positive half cycle will be
Correct!
Wrong!

For the circuit shown in the figure below, Vs is the ac voltage source with peak value Vm. The waveform of the load voltage at the resistor will have
Correct!
Wrong!

Consider the diode to be an ideal one and Vo = Vr + Vdc during positive half cycle. Thus, during the negative half cycle
Correct!
Wrong!

For the circuit shown below,
Vdc = 50 V
Cutin voltage for D1 = 0.2 V
Cutin voltage for D2 = 0.6 V
R = 5KΩ
Current through D1 & D2 would be,
Vdc = 50 V
Cutin voltage for D1 = 0.2 V
Cutin voltage for D2 = 0.6 V
R = 5KΩ
Current through D1 & D2 would be,
Correct!
Wrong!

For the circuit shown below, Vs=230V, Voltage drop across the diode (Vd) = 2V
The peak value of voltage at R in the positive and the negative half cycles are ___ & ___ respectively.
The peak value of voltage at R in the positive and the negative half cycles are ___ & ___ respectively.
Correct!
Wrong!

When diode is connected in series to an AC source & RL load, the conduction time for the diode
Correct!
Wrong!

The circuit shown below has the following parameters:
Voltage drop across D1 & D2 = 0.7 Volts
V1 = 8 Volts
V2 = 6 Volts
Vs = 10V/√2 (RMS)
At the load (R), the peak value in the negative half cycle is
Voltage drop across D1 & D2 = 0.7 Volts
V1 = 8 Volts
V2 = 6 Volts
Vs = 10V/√2 (RMS)
At the load (R), the peak value in the negative half cycle is
Correct!
Wrong!
