1P-Diode Half Wave Rectifiers Questions and Answers – Part 2

A 1-phase 230V, 1KW heater is connected across a 1-phase HW rectifier (diode based). The power delivered to the heater is

For the below given circuit, Vs = 325 sin ωt (secondary side) The ripple voltage is

For a single phase half wave rectifier, the rectifier efficiency is always constant & it is

A 1-phase half wave diode rectifier with R = 1 KΩ, has input voltage of 240 V. The diode peak current is

A 1-phase half wave diode rectifier with R load, has input voltage of 240 V. The input power factor is

For the below given circuit, The power delivered to the load in Watts is

For the below given circuit, after the switch is closed the voltage across the load (shown open) remains constant. Assuming that all initial conditions are zero. The element across the load would be a/an

For the below given circuit, After the supply voltage (Vs) is given the

For the below given circuit, With Vs = Vm sin ωt (secondary side). The expression for the average voltage is

For the below given circuit, the