1P-Diode Half Wave Rectifiers Questions and Answers – Part 1

In a half-wave rectifier, the

Find the rms value of the output voltage for the circuit shown below. Voltage across the secondary is given by Vm sinωt.

In a 1-Phase HW diode rectifier with R load, the average value of load current is given by Take Input (Vs) = Vm sinωt

In the circuit shown below, The switch (shown in green) is closed at ωt = 0. The load current or capacitor current has the maximum value at ωt =

Find the average value of output current for a 1-phase HW diode rectifier with R load, having RMS output current = 100A.

For a certain diode based rectifier, the output voltage (average value) is given by the equation 1/2π [ ∫Vm sin ωt d(ωt) ] Where the integral runs from 0 to π The rectifier configuration must be that of a

For a single phase half wave rectifier, with R load, the diode is reversed biased from ωt =

For the circuit shown below, The secondary transformer voltage Vs is given by the expression Vs = Vm sin ωt, Find the PIV of the diode.

In the process of diode based rectification, the alternating input voltage is converted into

For the circuit shown below, The peak value of the load current occurs at ωt = ?