4-20 mA transmitter current output can be converted to the voltage within a specified range, from 0 to a maximal amplitude Vmax, as shown in the following picture:
Where,
I is the current,
V is the voltage,
PV is the Process Variable
min is the Lower Range Value of the respective signal
max is the Upper Range Value of the respective signal
Note that the values and units of min and max are units must be same.
Example 1 :
I = ( ( (V − Vmin) / ( Vmax − Vmin) ) × 16 ) + 4
I = ( ( (2.5 − 0) / ( 5 − 0) ) × 16 ) + 4
I = 12 mA
Example 2 :
V = ( (I − 4 ) / 16) × ( Vmax − Vmin ) + Vmin
V = ((13.5 – 4)/16 x (10 – 0 ) + 0
V = 5.9375 V
Example 3 :
PV = ( (I − 4 ) / 16) × ( PVmax − PVmin ) + PVmin
PV = ( (16.5 − 4 ) / 16) × ( 1500 − 0 ) + 0
PV = 1171.87 m3/hr
Also Read : 4-20mA Transmitter Principle
The conveyor sorting machine is widely used in the packing industries using the PLC program…
Learn the example of flip-flop PLC program for lamps application using the ladder logic to…
In this article, you will learn the STAR DELTA programming using PLC controller to start…
Lube oil consoles of rotary equipment packages in industrial process plants are usually equipped with…
Rotating equipment packages such as pumps, compressors, turbines need the lube oil consoles for their…
This article explains how to blink lights in ladder logic with a detailed explanation video…
View Comments
Thanx, Realy it is important for me.
Thanks very much sir, this is very important.
pls how do i print it.
formula wrong ex: range -50 to 50 psi i get 12 mA what is the pv value?
Hi Balajee, Formula Working fine. Please see : PV = [ (12-4)/16 X { 50- (-50) } ] + (-50) = ( 0.5 X 100 ) - 50 = 0. Also Click Here to Use online Calculator for fast calculations.
yes Mr S Bharadwaj reddy its by mistake. Thanks 4 reply
I(mA)=16/(Vmax-Vmin)(V-Vmin)+4Vmax/(Vmax-Vmin)
0 psi
How amazing very good effort.
thanks
thank you brother
how to calculate the % of valve opening at milli ampere 4 to 20
Hi, For 4-20mA to 0 - 100 % Conversion : CLICK HERE
Thank you infomation.
how to calculate 4 to 20 mA for -17 to 187 Mwatts
4-20 mA for 0-1000kg sensor transducer, what is output for 850kg?