#### Foundation Fieldbus Pressure Transmitter Configuration

FF Pressure transmitter basic configuration parameters are L_Type, XD_Scale, OUT_Scale and Channel.

These parameters are configured in Analog Input (AI) Function block of FF transmitter.

The below problems shows the pressure transmitter configurations for different cases.

#### Problem 1 :-

**A pressure transmitter with a range of 0 â€“ 100 psi. How to configure a foundation fieldbus pressure transmitter ?**

Analog Input function block configuration for a typical pressure transmitter as per below table :

Here Primary_Value_Range : 0 to 100

**Problem 2 :-**

**The level of an open tank is to be measured using a pressure tap at the bottom of the tank. The maximum level of the tank is 16 ft. The liquid in the tank has a density that makes the maximum level correspond to a pressure of 7.0 psi at the pressure tap (see below Figure).**

The table below lists the appropriate configuration settings.

Analog Input function block configuration for a pressure transmitter used in level measurement (problem #1).

**Output calculation forÂ Problem 2 :**

When the L_Type is configured as Indirect, the OUT parameter is calculated as:

OUT = Â [ (PV â€“ XD_SCALE_0% ) / (XD_SCALE_100% â€“ XD_SCALE_0%) ] x ( (OUT_SCALE_100% â€“ OUT_SCALE_0%) + OUT_SCALE_0%)

In this example, when PV is 5 psi, then the OUT parameter will be calculated as follows:

OUT = Â [ (Â 5 psi â€“ 0 psi ) / (7 psi â€“ 0 psi) ] x ((16 ft â€“ 0 ft) + 0 ft ) =Â 11.43 ft

**Problem 3 :-**

**The transmitter in problemÂ #3 is installed below the tank in a position where the liquid column in the impulse line, with an empty tank, is equivalent to 2.0 psi (see Below Figure ).**

**Solution to ProblemÂ #3**

The table below lists the appropriate configuration settings.

Analog Input function block configuration for a pressure transmitter used in level measurement (Problem #3).

In this example, when the PV is 4 psi, OUT will be calculated as follows:

OUT = [ (4 psi â€“ 2 psi ) / (9 psi â€“ 2 psi) ] x (Â Â (16 ft. â€“ 0 ft.) + 0 ft.) =Â 4.57 ft.

**Differential pressure transmitter to measure flow**

**Problem 4 :-**

**The liquid flow in a line is to be measured using the differential pressure across an orifice plate in the line. Based on the orifice specification sheet, the differential pressure transmitter was calibrated for 0 to 20 inH2O for a flow of 0 to 800 gal/min.**

Solution

The table below lists the appropriate configuration settings.

Reference : Rosemount Pressure Transmitter Manual

## 3 comments

Excellent document to lean from Pressure Transmitter

Excellent……but plz explain zero elevation ( positive bias ) transmitter configuration

Hi, Already available in “Level Measurement” Category. Please check.