A circuit is so formed such that the source-R-C-diode-switch are in series. Consider the initial voltage across the C to be zero. The diode is so connected that it is forward biased when the switch is closed. When the switch is closed,

In the circuit show below, The initial current through the inductor is zero. When the switch (shown in green) is closed, then the current through the inductor

A diode circuit is so arranged that when the switch is open it’s KVL gives
Ri+ 1/C ∫i dt = 0
When the switch is closed,
Ri+ 1/C ∫i dt = Vs
Vs is the dc supply voltage.
The diode is so connected that it is forward biased when switch is closed
The circuit is mostly likely be a

In the figure shown below, As the switch (shown in the green) is pressed, the voltage across the diode(ideally)

The time constant of a series RL circuit (τ) is given by

In the figure shown below, When the switch is open, the voltage across the diode (ideally)

For a diode circuit the voltage across the capacitor is given by Vc(t)= Vs(1-e^(-t/RC)) Then the initial rate of change of capacitor voltage is given by

The time constant of a series RC circuit (τ) is given by

A circuit is so formed such that source-R-L-diode-switch are all in series. Consider the initial current in L to be zero. The diode is so connected that it is forward biased when switch is closed. When the switch is closed,

An ideal diode has _________ &__________